2x^2+2x=5x^2+4

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Solution for 2x^2+2x=5x^2+4 equation: 



2x^2+2x=5x^2+4

We move all terms to the left:

2x^2+2x-(5x^2+4)=0

We get rid of parentheses

2x^2-5x^2+2x-4=0

We add all the numbers together, and all the variables

-3x^2+2x-4=0

a = -3; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·(-3)·(-4)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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